Mechanics11/Seite5/Loesung2.8
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Lösung
a)
[math]a = \frac {\Delta v} {\Delta t} [/math] ==> [math]\Delta v = \Delta t * a [/math]
==> v1 = 20s * 0,5 m/s² = 10 m/s = 36 km/h
==> v2 = 40s * 0,1 m/s² = 4 m/s = 14,4 km/h
==> v1 + v2 = 50,4 km/h
--Kenny 12:21, 30 November 2007 (CET), --Marc 12:21, 30 November 2007 (CET)
b)
[math]x(t)= \frac{1}{2}*a*t[/math]
[math]x(20)= \frac{1}{2}*0,5\frac{m}{s^2}*(20s)^2 = 100m [/math]
[math]x(60)= 540m [/math]
[math]x(80)= 860m [/math]
x-Achse: [math]\frac{t}{s}[/math] y-Achse: [math]\frac{x}{m}[/math] --Max 12:24, 30 November 2007 (CET) --Gunacke 12:24, 30 November 2007 (CET)