Mechanics11/Seite11/Loesung4.1
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c) geg: m = 35t = 35000kg t = 40s v = 50kmh-1 = 13.8ms-1
ges: Wbesch
Lsg: Wbesch =0.5*m*v²
Wbesch = 0.5*m*v2
Wbesch= 0.5*(35000kg)*(13.8ms-1)2
Wbesch= 3332700J
d) geg: m = 35t = 35000kg t = 40s v = 50kmh-1 = 13.8ms-1
ges: P Lsg: P = [math]\frac{W}{t}[/math] P = [math]\frac{3332700J}{40s}[/math] P = 83317.5W = 83.3175kW = 83kW
--Klaksa 13:06, 25 January 2008 (CET)
Ich bedanke mich bei meiner Banknachbarin, durch die mir das Lösen der Aufgabe ermöglicht wurde...
c) m = 35t = 35000kg
t = 40s
v = 50kmh-1 = 13.8ms-1
Wa = 0.5*m*v2
= 0.5*(35000kg)*(13.8ms-1)2
= 3332700J
d) P = [math]\frac{W}{t}[/math]
= [math]\frac{3332700J}{40s}[/math]
= 83317.5W = 83.3175kW
--Anki 13:11, 25 January 2008 (CET)
4.2 Brummi
m=35t =3500 kg steigung =10%
konstante beschleunigung nach 200 m =>v =50 km/h
a)v^2 = 2 a x
=> a=v^2/2x =13,8m/s/
[math]\frac{13,8 m/s}{2*200m}[/math]
--Valerie 13:05, 1 February 2008 (CET)