Factoring Polynomials

If you know your times tables, factoring polynomials can be a straight forward task. Just as you know that the factors of 27 are nine and three, so will you come to recognized the factors of most common polynomials. Here's a simplified approach to the five most common types. With this info readily at hand, identify the type of polynomial you are factoring and follow the appropriate model. Pretty soon you won't have any more problems factoring polynomials.

Difference of Squares

a² - b²

factors to

(a - b)(a + b).

Note how the middle "ab" terms cancel one another out. Verify that's the case by multiplying your factored form to see that it works back to the polynomial you started with.

Here's an example.

x² - 16 = (x - 4)(x + 4)

when you multiply the each elements of RHS with each other here you get a common term 4x with opposite sign which cancel each other.

Factoring the type a² +2ab + b²

a² +2ab + b²

factors to

(a + b)(a + b).

Note how the middle" ab" terms add to one another. Verify that's the case by multiplying your factored form to see that it works back to the polynomial you started with.

Here's an example.

x² + 8x + 16 = (x + 4)(x + 4)

Here too same as above procedure.

Factoring the type a² - 2ab + b²

a² -2ab + b²

factors to

(a - b)(a - b).

Note that a negative times a negative is a positive. Also note how the middle negative ab terms are collected. Verify that's the case by multiplying your factored form to see that it works back to the polynomial you started with.

Here's an example.

x² - 8x + 16 = (x - 4)(x - 4)

Factoring the type a³ - b³

a³ - b³

factors to

(a - b)(a² +ab + b²).

Note that a negative times a positive is a negative. Also note how the middle positive ab term cancels out the middle terms. Verify that's the case by multiplying your factored form to see that it works back to the polynomial you started with.

Here's an example.

x³ - 27 = (x - 3)(x +3x + 9)

Factoring the type a³ + b³

a³ + b³

factors to

(a + b)(a² -ab + b²).

Note that a negative times a positive is a negative. Also note how the middle positive ab term cancels out the middle terms. Verify that's the case by multiplying your factored form to see that it works back to the polynomial you started with.

Here's an example.

x³ + 27 = (x + 3)(x -3x + 9)

Hello Martin, you might be interested in this resource: Help Page: LaTeX SYMBOL TABLES. Cheers --Gladys Gahona C. 03:21, 10 December 2010 (UTC) (: Created a page on hands on activities on verifying cubic identities http://wikieducator.org/Hands_on_Mathematics --Rashkath 16:22, 5 October 2011 (UTC))