Mechanics11/Seite10/Loesung3.17
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< Mechanics11 | Seite10
Angabe
- geg.: Höhe (h = 15m)
- ges.: Anfangsgeschwindigkeit (v0); Steigzeit (ts); Fallzeit (tf)
Rechnung
[math]h = 15m \frac{}{}[/math]
[math]h = \frac{v_2}{2g}[/math]
[math]v_0 = \sqrt[]{30 * 9.81}\frac{m}{s}[/math]
[math]v_0 = 17,16 \frac{m}{s}[/math]
[math]t_s = \frac{v_0}{g}[/math]
[math]t_s = \frac{17,6}{9,81}s[/math]
[math]t_s = 1,75 s \frac{}{}[/math]
[math]t_s = t_f \frac{}{}[/math]
[math]t_s = 1,75 s \frac{}{}[/math]
--FatF 12:25, 11 January 2008 (CET)
Schülerlösung
geg: h = 15m
ges: ts; v0; tf
h = v2/2g
v0 = [math]\sqrt[]{2g * h}[/math]
v0 = [math]\sqrt[] {2*9,81 m/s^2*15m}[/math]
v0 = 17,1 m/s