Mechanics11/Seite9/Loesung3.7
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< Mechanics11 | Seite9
Gegeben:
m = 0,50 kg ; v = 100 km/h
a)
Bremsweg: x = 10cm
v² = 2ax
a = v²/2x
a = (100km/h)² / 2*10cm
a = (27,78 m/s)² / 0,2m
a = 3858,642 m/s²
F = 0.5kg*3858 m/s² = 1918.2 N = 1.918 kN b)
2.Lösung
a) F = m*a
a = [math]\frac {v}{t}[/math] v²= 2ax a = [math]\frac {v\ltsup\gt2\lt/sup\gt}{2x}[/math] a = [math]\frac {27.7m/s²}{0,2m}[/math]