Mechanics11/Seite9/Loesung3.5

m = 6,0t
m = 6000kg
F = 20 kN
a)
[math]F = m*a [/math]

[math]\frac{F}{m}= a[/math]

[math]\frac{20000N}{6000kg}= a[/math]

[math]=\gt 3,334\frac{m}{s^2}[/math]

b.)

[math]\Delta t = \frac{\Delta v}{m}[/math]

[math]\Delta t = \frac{360 \frac{km}{h}}{\frac{m}{3s^2}}[/math]

[math]\Delta t = \frac{100 \frac{m}{s}}{\frac{m}{3s^2}}[/math]

[math]\Delta t = 30 s \frac{}{}[/math]

--FatF 12:19, 7 December 2007 (CET)

c)
[math]x(t)=\frac {1} {2}*a*t^2[/math]
[math]x(t)=\frac {1}{2}*3,334\frac{m}{s^2}*(30s)=1500m=1,5km[/math]

Schülerlösung

geg: m = 6,0t F = 20kN

a) ges: a

a = [math]\frac {F}{m}[/math]

a = [math]\frac {20kN}{6,0t}[/math]

a = [math]\frac {20000N}{6000kg}[/math]

a = 3,3m/s²

b) ges: t

v = 360km/h = 100m/s

t = [math]\frac {V}{a}[/math]

t = [math]\frac {100m/s}{3,3m/s^2}[/math]

t = 30,3s

c) ges: x

x = [math]\frac {1}{a}[/math] * t²

x = [math]\frac {1}{2}[/math] * 3,3m/s^2 * (30s)^2

x = 1485m = 1,5 km

von Natalia Dobrzycka 11B