Mechanics11/Seite14/Loesung5.7
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< Mechanics11 | Seite14
a)
v = [math]g * r[/math] = [math]9,81 m/s\ltsup\gt2\lt/sup\gt * 1,0m[/math] = 3,1m/s
b)
Epot = Ekin
m * g * h = 1/2 * m * v2 - 1/2 * m * v02
g * 2 * r = 1/2 * (v2 - v02)
4 * g * r = v2 - v02
v2 = v02 + 4 * g * r = (3,12 + 4 * 9,81 * 1,0) (m/s)2
=> v = 7,0 m/s
c)
h = v2/2*g = (3,1)2/(2*9,81) = 0,5m
Insgesamt fliegt die Dose 1.5m hoch.
--Chantal 08:20, 26 June 2008 (UTC)