Lesson 10: Simple Linear Equations
Topic 1: Indices and Logarithms | |
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Indices and Logarithms | Lesson 1: Bases and Indices | Lesson 2: Fractional Indices | Lesson 3: Zero and Negative Indices | Lesson 4: Exponential Equations | Lesson 5: Definition and Laws of Logarithms | Lesson 6: Equations Involving Logarithms | Lesson 7: Introduction to Surds | Lesson 8: Linear Equations | Lesson 9: Simultaneous Equations | Lesson 10: Simple Linear Equations |
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Contents
Introduction
In general linear equations are found in most calculations in science.In chemistry for example,linear equations are used in balancing chemical equations.In physics newton's laws of motion are mostly linear equations.
Definiton
A linear equation is defined as an equation where the greater power of the unknown is one.
Examples
- x+5=12
- 5x-3=44
- x=9
In all the above examples the highest power of x is one
Solving simple linear equations
To solve simple linear equations the following points should be noted;
- the sign of any term changes when it is moved from either side of the equal sign to the other e.g from the left-handside{L.H.S}to the right-handside{R.H.S}or vice visa.
- Any operation you do to the left,you must do to the right,this is because the equation will change otherwise.
Example1
Solve the equation x+3=4
solve the equation 33x-22=44
Solution
since x is on the left-handside of the equal sign ,we simply move 3 to the other side of the equal sign giving; x = 4-3 therefore x = 1 is the answer.
5 - x = 14
Example2
Solve the equation 2x+2=6
solve the equation 10x-22=44
Solution
First we move 2 to the right of the equal sign which gives 2x=6-2 this gives us 2x=4; since we are solving for x, we divide both sides of the equal equal sign by 2 thus: 2x/2 = 4/2 by cancellation on both sides we get x = 2
6 - 3x = 7
Example3
Solve the equation 3x-3=x+7
Solution
Since we have terms in x on both sides of the equation, we collect like terms together ;this gives 3x - x = 7 + 3 therefore 2x = 10 hence x = 5
6x - 8 = 5 - 2x
Equations containing brackets
Example4
Solve 2(x - 3) = 6 -3(x - 2)
solution
we first open the bracket
2x - 6 = 6 - 3x + 6
we collect like terms
2x + 3x = 6 + 6 + 6
5x = 18
we divide both sides by 5
x = 18/5 ans
example 5
Solve the equation -2(2x-3) -5 = 9(x-2)
solution
we open the brackets
-4x + 6 -5 = 9x - 18
we collect like terms
9x + 4x = 18 + 6 - 5
15x = 19
x = 19/15 ans