CFOS/FTE/Exercise 8.4
From WikiEducator
<Return to Unit 8
Establishing Equivalency with Full-Time Students in Conventional Education
EXERCISE 8.4 – Systems Approach
This example uses the same scenario as in the previous exercises, which were based on the Dublin Open School. The table of data is reproduced below for ease of reference.
Because of concerns about the internal efficiency and cost effectiveness of the Dublin Open School, its Board decided to adopt the Systems Approach to establish equivalency with full-time students in the formal education system.
- Calculate FTE student numbers for the Open School based on the systems approach.
Use the following EQUATION to carry out the calculation:
- FTESA = TESPODL ÷ (TESPFT / (TSFFT + TSFT-1 + TSFT-2. . .))
Where:
- FTESA = FTE Measure D: Systems Approach
- TESPODL = Total Examination Subject Passes by ODL students in current year
- TESPFT = Total Examination Subject Passes by Full-Time students in current year
- TSFT = Total number of Full-Time Students in current year
- TSFFT-1 = Total number of Full-Time Students in previous year
- TSFT-2 = Total number of Full-Time Students in the next previous year
2003 | 2004 | 2005 | ||
Dublin Open School | ||||
TSODL | Total Student Numbers (JSC Course) | 6,131 | 6,529 | 6,637 |
TSEODL | Total Subject Enrolments | 15,972 | 16,660 | 17,258 |
TESEODL | Total Examination Subject Entries | 13,112 | 14,023 | 14,962 |
TESPODL | Total Examination Subject Passes | 9,788 | 10,544 | 11,989 |
Junior Secondary Schools | ||||
TSFT | Total Student Numbers (Grade 10) | 32,804 | 33,013 | 32,751 |
TSFT-1 | Total Student Numbers (Grade 9) | 34,122 | ||
TSFT-2 | Total Student Numbers (Grade 8) | 35,418 | ||
ASEFT | Average Subject Enrolments per Year | 9 | 9 | 9 |
YFT | Number of Years at this Level/Phase | 3 | 3 | 3 |
TESEFT | Total Examination Subject Entries | 286,226 | 291,147 | 283,951 |
TESPFT | Total Examination Subject Passes | 254,741 | 262,039 | 258,963 |