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User:Rafael

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Hello

I´m Rafael and I go to the Gisela-Gymnasium in Munich which is a secondary school.I take part in the physics project of White Eagle.


Aufgaben

Gruppe A

a)


b) 

  Δt = t2 − t1 = 0,30s
  x_1=v_s* \frac {\Delta t} {2} 
  x_1=340 \frac {m} {s} *0,15s 
  x1 = 51m
  x2 = 170m
  Δx = (170 − 51)m = 119m
  Δt = 4,30s − 0,80s = 3,5s
  v= \frac {\Delta x} {\Delta t}=34\frac {m} {s}=122\frac {km} {h}

c) 

  x = x0 + v * t
   =  > x0 = x − v * t
  x_0=51m-34\frac {m} {s} *0,80s
  x0 = 24m

Aufgabe 2.1

Punkte Abstand Gescwindigkeit
1-2 0,45mm 22,5\frac {mm} {s}
2-3 1mm 50\frac {mm} {s}
3-4 2mm 100\frac {mm} {s}
4-5 2,22mm 111\frac {mm} {s}
5-6 2,7mm 135\frac {mm} {s}
6-7 3,4mm 170\frac {mm} {s}
7-8 3,6mm 180\frac {mm} {s}
8-9 4,3mm 215\frac {mm} {s}
9-10 4,8mm 240\frac {mm} {s}
15-16 7,5mm 375\frac {mm} {s}
20-21 10mm 500\frac {mm} {s}
25-26 12,9 645\frac {mm} {s}
30-31 15mm 750\frac {mm} {s}
33-34 16mm 800\frac {mm} {s}

Aufgabe 2.2

Die Beschleunigung bei 2.2 ist kleiner als die bei 2.1, da auf die gleiche Fläche mehr Punkte passen als bei 2.1

Aufgabe 4.3

F = 50N s = 80cm = 0,8m

a)
D = \frac {F} {s}
D = \frac {50N} {0,8m}
D = 62,5\frac {N} {m}
W = \frac {1} {2}D s^2
W = \frac {1} {2} 62,5\frac {N} {m} (0,8m)^2
W = 20J
b)
s = 0,8m + 0,5m = 1,3m
W = \frac {1} {2} D s^2

Aufgabe 4.14

m1 = 0,060kg

m2 = 11kg

v_1=1100\frac{m}{s}

a)

Der Rückstoß kommt zustande, da die Kraft der Explosion sowohl auf die Kugel als auch auf das Gewehr wirkt.

b)

m2 = 11kg

p = m1 * v11

p=0,060kg*1100\frac {m} {s}

p = 66Ns

p = − p'

p' = m2 * v2

v_2=\frac {-p} {m_2}

v_2=\frac {-66Ns} {11kg}

v_2=-6\frac {m} {s}

c)

F?

t = 0,20s

Δp = F * Δt

=> F=\frac {\Delta p} {\Delta t}

F=\frac {66Ns} {0,20s}

F = 330N


Aufgabe 1.6

a) x(t)_F =0km+153 \frac {km}{h} *t
x(t)_B=14km+95 \frac {km}{h} *t
x(t)F = x(t)B
153 \frac {km}{h} *t=14km+95\frac {km}{h}*t
58\frac {km}{h}*t=14km
t = 0,24h
x(t) = 37km

b) t_B=\frac {x}{v}=\frac {26km}{95\frac {km}{h}}=0,273h
t_F=\frac {x}{v}=\frac {40km}{153\frac{km}{h}}=0,261h

Aufgabe 2.9

a) x(t)=\frac {1}{2}*a*t^2 

  t=2\frac {x(t)}{v}=2\frac {0,80m}{760\frac{m}{s}}=2,1*10 s

Aufgabe 4.6

a) E_k = \frac {1}{2}m*v^2 = \frac {1}{2}*2000kg*\frac {50}{3,6}\frac{m}{s} = 193KJ
b) E_p = m*g*h = 9,81 \frac {N}{kg}*200m*1000kg = 1962000J
c) E_k = \frac {1}{2}*4000000kg*1\frac{m}{s} = 2MJ

Aufgabe 5.1

a) T=\frac{5*60}{13}s=23s

  f=\frac{1}{T}=\frac{1}{23}\frac{1}{s}=0,043Hz

  w=\frac{2pi}{T}=0,272\frac{1}{s}

b) w=\frac{\Delta phi}{\Delta t}

  Failed to parse (lexing error): \Delta phi=w* \Delta t=0,272*10=2,272= \frac{2,72}{2pi}*360°=156°


"Sandbox"

abcdefg

abcdefg

abcdefg

x(t) = x0 + v * t

Δx = v * Δt

v = \frac {x}{t}

v = \frac {x_1-x_0}{\Delta t}

x1(t) = x2(t)

x1 + v1 * t = x2 + v2 * t

x1 − x2 = (v2 − v1) * t

t = \frac {x_1-x_2}{v_2-v_1}

t = \frac {173m-25m}{28 \frac {km}{h}-11 \frac {km}{h}}

--Rafael 12:16, 5 October 2007 (CEST)


Schön, dass Sie an der Lösung dieser Aufgabe gearbeitet haben!--White Eagle 12:17, 22 October 2007 (CEST)

Testgraph

Image:testgraph.gif

--Rafael 12:03, 9 November 2007 (CET)

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