Mechanics11/Seite9/Loesung3.5

m = 6,0t
m = 6000kg
F = 20 kN
a)
$F = m * a$

$\frac{F}{m}= a$

$\frac{20000N}{6000kg}= a$

$=> 3,334\frac{m}{s^2}$

b.)

$\Delta t = \frac{\Delta v}{m}$

$\Delta t = \frac{360 \frac{km}{h}}{\frac{m}{3s^2}}$

$\Delta t = \frac{100 \frac{m}{s}}{\frac{m}{3s^2}}$

$\Delta t = 30 s \frac{}{}$

--FatF 12:19, 7 December 2007 (CET)

c)
$x(t)=\frac {1} {2}*a*t^2$
$x(t)=\frac {1}{2}*3,334\frac{m}{s^2}*(30s)=1500m=1,5km$

Schülerlösung

geg: m = 6,0t F = 20kN

a) ges: a

a = $\frac {F}{m}$

a = $\frac {20kN}{6,0t}$

a = $\frac {20000N}{6000kg}$

a = 3,3m/s²

b) ges: t

v = 360km/h = 100m/s

t = $\frac {V}{a}$

t = $\frac {100m/s}{3,3m/s^2}$

t = 30,3s

c) ges: x

x = $\frac {1}{a}$ * t²

x = $\frac {1}{2}$ * 3,3m/s^2 * (30s)^2

x = 1485m = 1,5 km

von Natalia Dobrzycka 11B