Mechanics11/Seite9/Loesung3.5
m = 6,0t
m = 6000kg
F = 20 kN
a)
[math]F = m*a [/math]
[math]\frac{F}{m}= a[/math]
[math]\frac{20000N}{6000kg}= a[/math]
[math]=\gt 3,334\frac{m}{s^2}[/math]
b.)
[math]\Delta t = \frac{\Delta v}{m}[/math]
[math]\Delta t = \frac{360 \frac{km}{h}}{\frac{m}{3s^2}}[/math]
[math]\Delta t = \frac{100 \frac{m}{s}}{\frac{m}{3s^2}}[/math]
[math]\Delta t = 30 s \frac{}{}[/math]
--FatF 12:19, 7 December 2007 (CET)
c)
[math]x(t)=\frac {1} {2}*a*t^2[/math]
[math]x(t)=\frac {1}{2}*3,334\frac{m}{s^2}*(30s)=1500m=1,5km[/math]
Schülerlösung
geg: m = 6,0t F = 20kN
a) ges: a
a = [math]\frac {F}{m}[/math]
a = [math]\frac {20kN}{6,0t}[/math]
a = [math]\frac {20000N}{6000kg}[/math]
a = 3,3m/s²
b) ges: t
v = 360km/h = 100m/s
t = [math]\frac {V}{a}[/math]
t = [math]\frac {100m/s}{3,3m/s^2}[/math]
t = 30,3s
c) ges: x
x = [math]\frac {1}{a}[/math] * t²
x = [math]\frac {1}{2}[/math] * 3,3m/s^2 * (30s)^2
x = 1485m = 1,5 km
von Natalia Dobrzycka 11B