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Mechanics11/Seite9/Loesung3.4

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a) a = \frac{v}{t}

daraus folgt: 



     a = \frac{45 m/s}{30s} = 1.5 \frac{m}{s^2}


b) F = a*m

daraus folgt: 


      m = \frac{F}{a} = \frac{1000 N}{1.5 m/s^2} = 666.7 kg


c) 

      m' = 1.5 * m = 666.7 kg * 1.5 = 1000 kg




      a = \frac{F}{m} = \frac{1000 N}{1000 kg} = 1.0 \frac{m}{s^2}




       v = a*t = 1.0 \frac{m}{s^2} * 30s = 30 \frac{m}{s}


Schülerlösung

geg: t=30s F=1000N v = 45 m/s


a) ges: a

v = a * t

a = \frac {v}{t}

a = \frac {45m/s}{30s}


a = 1,5 \frac {m}{s^2}

b) ges: m

F = m * a

m = \frac {F}{a}


m = \frac {1000}{1,5m/s^2}


m = 666,66kg = 0,67t

c)

a = \frac {F}{m}

v = a * t = \frac{F}{m} * t

v = \frac {1000N}{1,5 * 667kg} * 30s = 29,985 m/s


von Natalia Dobrzycka 11B

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