Chemistry/Equilibrium Titration
The object of this experiment is to determine the value of the equilibrium constant for the following reaction using a titration procedure.
(1)
We will start with a solution containing equal concentrations of Ag+ and Fe2+ and allow the mixture to come to equilibrium according to equation (1). As can be seen from the reaction equation, the moles of Ag+ which react equals the moles of Fe2+ which react. Also, the moles of Fe3+ which form equal the moles of Fe2+ which react.
When equilibrium has occurred, a sample of the equilibrium mixture is reacted with SCN– solution until all the Ag+ remaining at equilibrium is precipitated as AgSCN(s).
Procedure
That is, the number of moles of Ag+ present at equilibrium equals the number of moles of SCN– which are added from the burette. When all of the Ag+ has been removed from solution, the addition of one excess drop of SCN– causes the Fe3+ produced in the equilibrium reaction to form the complex ion FeSCN2+, which has an intense red colour:
Therefore, the Fe3+ acts as an indicator: when the solution being titrated takes on an orange tint, the titration is at the endpoint. (The solution would be red if sufficient FeSCN2+ were present, but at low concentrations the coloration is orange.)
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Calculations
1. Recall that when two solutions mix, they dilute each other as follows.
[solution #1]DILUTED = [solution #1]BEFORE MIXING [math] * \frac {Volume\ of\ solution\ 1} {Volume\ of\ mixture} [/math]
When the AgNO3 solution is mixed with the Fe(NO3)2 solution, the two solutions dilute each other.
(a) Calculate the [Ag+ ] after the dilution.
(b) Calculate the [Fe2+ ] after the dilution.
These values represent the "starting [Ag+ ] and [Fe2+ ] in the solution".
2. Use the [KSCN] (that is, [SCN– ]) and the average volume of KSCN added in the titrations to calculate the moles of SCN– added.
3. (a) Based on equation (2), how many moles of Ag+ are present in the 25.0 mL sample of the equilibrium mixture you titrated? Based on the number of moles of Ag+ present in 25.0 mL of the mixture, what [Ag+ ] exists in the 25.0 mL sample at equilibrium?
(b) Using the starting [Ag+ ], found in calculation 1(a), and the [Ag+ ] existing at equilibrium, as found in calculation 3(a), calculate the decrease in [Ag+ ] occurring when the starting mixture reaches equilibrium. Note that we calculate changes in concentration in the same way that we calculate changes in moles: since all the concentrations refer to the same volume, then
- equilibrium moles = starting moles – change in moles
- and equilibrium [ ] = starting [ ] – change in [ ] .
Now that you have calculated the "change in [Ag+ ]", by how much will the [Fe2+ ] DECREASE at the same time, according to equation (1)? Based on this "change in [Fe2+ ]" and the starting [Fe2+ ], found in calculation 1(b), what is the equilibrium [Fe2+ ]?
(c) What is the starting [Fe3+ ] (before the reaction starts)? NOTE: [Fe3+ ], NOT [Fe2+ ] ! According to equation (1), by how much does the [Fe3+ ] INCREASE when the reaction comes to equilibrium? What is the equilibrium [Fe3+ ]?
4. Write out the equilibrium expression for reaction (1).
5. Using the results you arrived at in Calculation 3, calculate the value of the equilibrium constant for equation (1).