Template:Flickrreview/doc

{{TemplateBox
 * 1=1
 * 1d=username of the reviewing user
 * 2=2
 * 2d=date of the review in ISO 8601 format
 * 3=3
 * 3d=name of the unfree license on Flickr, if review failed
 * 4=changed
 * 4d=name of the license of the original upload on Commons if it was found different from the free license on Flickr at the time of review and then changed by the reviewer
 * name=Flickrreview
 * desc=Used to report Flickr review status. See also User:FlickreviewR.

Instructions for reviewers

 * 1) The image is initially in Category:Flickr review needed.
 * 2) If the image is currently available on Flickr under the same license as on the Commons, modify the review template to  . This places it in Category:Admin reviewed Flickr images.
 * 3) If the image is currently available on Flickr under a license which is allowed on the Commons, but the license on Commons is not the same (such as an older version of the same license), update the license tag on the Commons image to match the Flickr one and modify the review template to  . This places it in Category:Admin reviewed Flickr images.
 * 4) If the licence is allowed on the Commons, сheck if the author is properly attributed.
 * 5) If the image is currently available on Flickr with a license which is not acceptable on Commons, do not update the license tag. Instead modify the review tag to  . This places it in Category:Possibly unfree Flickr images.
 * 6) Please leave a comment on the photo, such as "Thanks for licensing this CC-BY! Your choice of a free license has allowed us to use your image in Wikimedia Commons ( http://commons.wikimedia.org/ )." to confirm that the photographer did not make a mistake in their license selection and to encourage them to join our community.
 * namespace=File
 * usergroup=all
 * usage-notes=

Example of unfree image tag


}}
 * type=marker
 * example=
 * i18n-method=autotranslate
 * i18n-desc=
 * seealso=
 * setscats=Category:Possibly unfree Flickr images or Category:Admin reviewed Flickr images
 * lines=one
 * shorthand=