Mechanics11/Seite14/Loesung.5.1

a) T= $$\frac {5 *60}{13}s$$ = 23s

f= $$\frac {1}{T}$$ = $$\frac {1}{23}s$$= 0,043Hz

ω = $$\frac {2\pi}{T}$$ = 2πf=0,272Hz

b) ω = $$\frac {\Delta \varphi}{t}$$

φ=ω * t= 0,272*10=2,72 entspricht 156°

t = $$\frac {\varphi}{\omega}$$