Mechanics11/Seite11/Loesung4.3

a)

$$D = \frac {F}{s}$$

$$D = \frac {50N}{0,80m}$$

$$D = 62,5 \frac {N}{m}$$

$$W_sp = \frac {1}{2} * D * s^2$$

$$W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 0,80m^2 = 20 J $$

b)

$$W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 1,30m^2 = 52,8 J$$

52,8J - 20J = 32,8J

c)

$$E = W_gesp.$$

=> E = 52,8J

-Marc Schuster, Sebastian Felsner, Maximilan Vrecko-

Zusätzliche Schülerlösung
geg.:
 * F = 50 N
 * s = 80 cm

ges.:
 * D
 * WSp

a)

$$D = \frac{F}{s}$$

$$D = \frac{50 N}{0,8 m}$$

$$D = 62,5 \frac{N}{m}$$

$$W_Sp = \frac{1}{2} D * s^2$$

$$W_Sp1 = \frac{1}{2} 62,5 \frac{N}{m} * (0,8 m)^2$$

$$W_Sp1 = 20 J \frac{}{}$$

b)

geg.: s_2 = 50 cm + 80 cm = 1,3 m

ges.: WSp2

$$W_Sp2 = \frac{1}{2} 62,5 \frac{N}{m} * (1,3 m)^2 - W_Sp1$$

$$W_Sp2 = 52,8 J - 20 J = 32,8 J \frac{}{}$$

c)

ges.: F

$$F = D * s \frac{}{}$$

$$F = 62,5 \frac{N}{m} * 1,3 m$$

$$F = 1,3 N \frac{}{}$$

--FatF 12:07, 25 January 2008 (CET)