User:Marcosm11

Greetings, my name is Marco and I go currently to the Gisela-Gymnasium in munich. This page is about physics, yay!

Lösung zu 1.6 "Wettflug" 

x(t)=x0+v* $$\delta {t}$$

Bussard:x(t)=14km+95 $$\frac {km}{h}$$* $$\delta {t}$$

Falke:x(t)=0km+153 $$\frac {km}{h}$$* $$\delta {t}$$

Gleichgesetzt:14km+95 $$\frac {km}{h}$$* $$\delta {t}$$=0km+153 $$\frac {km}{h}$$* $$\delta {t}$$

a)

x(t)= x0+ Δt * v x(tF)= 14km+ 95km/h * Δt x(tB)= 0km+ 153km/h * Δt

x(tF)=x(tB) 14km + 95km/h * Δt= 153km/h * Δt 14km = 58km/h * Δt 0,24h=Δt 14min= Δt

b) x(0,24h) = 153km/h * 0,24h x(0,24h)= 36,7km x(14min)= 37 km

c) Der Falke überholt den Bussard bei 37 Kilometern.

Lösung zu 2.7 "Von Null auf Hundert"

geg: v(t) = 100 km/h ; t = 3,87s

ges: a ; x(t)

$$a=\frac{v(t)}{t}=\frac{100\frac{km}{h}}{3,87s}= \frac{2,8\frac{m}{s}}{3.87s}=7.12\frac{m}{s^2}$$

$$x(t)=\frac{1}{2}*a*t^2=\frac{1}{2}*7.12\frac{m}{s^2}*(3,87s)^2=53,75m$$

Lösung zu 3.20

geg m = 35t= 35000kg ; Steigung = 10% ; x = 200m ; v = 50 km/h ; µ = 0.15

a)

ges a

lsg v²=2ax                                     µµµµµµµµµ

$$a=\frac{v^2}{2*x}$$

$$a=\frac{50^2}{2*200}=6.25\frac{m}{s^2}$$

b)

ges  F_Motor

lsg  $$F_G=35000kg*9.81\frac{N}{kg}$$

$$F_H=F_G*sin alpha$$

F_Motor=F_R+F_H+F_a

F_Motor=F_N+m*a+F_H

F_Motor