Mechanics11/Seite11/Loesung4.1

c) geg: m = 35t = 35000kg t = 40s  v = 50kmh-1 = 13.8ms-1

ges: Wbesch

Lsg: Wbesch =0.5*m*v²

Wbesch = 0.5*m*v2

Wbesch= 0.5*(35000kg)*(13.8ms-1)2

Wbesch= 3332700J

d) geg: m = 35t = 35000kg  t = 40s  v = 50kmh-1 = 13.8ms-1   ges:  P   Lsg:  P = $$\frac{W}{t}$$         P = $$\frac{3332700J}{40s}$$         P = 83317.5W = 83.3175kW = 83kW

--Klaksa 13:06, 25 January 2008 (CET) Ich bedanke mich bei meiner Banknachbarin, durch die mir das Lösen der Aufgabe ermöglicht wurde...

c) m = 35t = 35000kg t = 40s v = 50kmh-1 = 13.8ms-1

Wa = 0.5*m*v2 = 0.5*(35000kg)*(13.8ms-1)2 = 3332700J

d) P = $$\frac{W}{t}$$ = $$\frac{3332700J}{40s}$$ = 83317.5W = 83.3175kW

--Anki 13:11, 25 January 2008 (CET)

4.2 Brummi

m=35t =3500 kg steigung =10%

konstante beschleunigung nach 200 m =>v =50 km/h

a)v^2 = 2 a x

=> a=v^2/2x =13,8m/s/

$$\frac{13,8 m/s}{2*200m}$$

--Valerie 13:05, 1 February 2008 (CET)