Mechanics11/Seite10/Loesung3.14

Lösung zu 3.14:

a) ges: x

geg: t1 = 6,024 s

Lsg: xB1 = 1/2 * a * ( Δt )2

xB1 = 1/2 * 9,81 N/kg * ( 6,024 s )2 = 177,995 m

xB1 = 178m

b) geg: vs = 340 m/s, xB1 = 178 m

ges: t2

Lsg: v = Δx / Δt

t2 = $$\frac{178 m}{340 m/s}$$ = 0,524 s

c) ges: xB2

geg: t1 - t2 = 5,5 s

Lsg: x = 1/2 * 9,81 N/kg * ( 5,5 s )2 = 148,38 m       xB2 = 148 m

--Franzi-frasiM11 12:13, 16 February 2009 (UTC)