Mechanics11/Seite4/Loesung1.9

= Lehrerlösung =

a) $$\Delta x$$ = 0 - 168 m = - 168 m

$$\Delta t$$ = 12,5 s

⇒ v = - 13,4 m/s = - 48,3 km/h

b) x1 = x0 + v⋅t1

= 168 m + ( - 13,4 m/s)⋅173 s

= - 2,16 km

c) $$t_2 = \frac{x_2 - x_0}{v}$$ $$= \frac{- 6,2 km - 168 m}{- 13,4 m/s}$$ = 7 min 54 s