Mechanics11/Seite15/Loesung5.12

$$m_1 =47 kg m_2 =60kg G= 6,67*10^-11\frac{m^3}{kg*s^2}$$

$$F=\frac{m_1*m_2}{r^2}*G$$

$$F=6,67*10^-11*\frac{m^3}{kg*s^2}*\frac{60kg*47kg}{0,5m^2}$$

$$F= 7,5*10^-11N$$

--Max 07:54, 26 June 2008 (UTC)