Mechanics11/Seite9/Loesung3.7

Gegeben:

m = 0,50 kg ;   v = 100 km/h

a)

Bremsweg: x = 10cm

v² = 2ax

a = v²/2x

a = (100km/h)² / 2*10cm a = (27,78 m/s)² / 0,2m

a = 3858,642 m/s²

F = 0.5kg*3858 m/s² = 1918.2 N = 1.918 kN b)

2.Lösung
a) F = m*a  a = $$\frac {v}{t}$$   v²= 2ax   a = $$\frac {v2}{2x}$$   a = $$\frac {27.7m/s²}{0,2m}$$