User:Zlodziejka

i am a student at giselagymnasium

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x(t) = x0+vt

$$\Delta x$$ = v $$\Delta t$$

v = $$\frac {x}{t}$$

v = $$\frac{x_1 - x_0}{\Delta t}$$

x1 (t) = x2 (t)

x1 + v1t = x2 + v2t

x1 - x2 = (v2 - v1) * t

t = $$\frac{x_1 - x_2}{v_2 - v_1}$$

= $$\frac{173m - 25m}{28}$$

a) ges: Fahrzeuggeschwindigkeit $$\Delta x$$ = 0 - 168 m = - 168m $$\Delta t$$ = 12,5 sekunden

$$\frac{\Delta x}{\Delta t}$$ = v v = - 13,44m/s = -48,3km/h b) t = 2 min 53 sek

168m + ( -13,4m/s ) 173s

= - 2,16km

Schön, dass Sie an der Lösung dieser Aufgabe gearbeitet haben!--White Eagle 12:11, 22 October 2007 (CEST)

c) t =







übersetzung:

it follows in this case:

a= $$\frac{v}{t}$$

(movement with constant aceleration from that rests)

if the venture owns already at the beginning of the movement a beginning speed $$v_0$$ so the functional equation is

v(t) = $$v_0$$ + at

the graph is origin-straight a postponed:



(1) $$\Delta t$$

(2) $$\Delta v$$

(3) $$v_0$$

(4) $$t_0$$

It turns out for a>0 a movement with consistently acceleration, for a<0 a movement with consistently speed and for a=0 a movement with consistently delay ( falling graph)

!Attention! This time the formula a = $$\frac{v}{t}$$ is wrong!!

To be used is:



a is also the gradient of the line.

Definition:The acceleration a is the gradient of the t-v-line.

The unit of the acceleration is m/s².

2.3: Accelerationtest

A testinstitution analyses the movement of a vehicle.The results are:

a) Draw a t-v-diagramm! (10s=1 cm, 1m/s=1 cm)

b) Name the type of movement in the particular timezones!

c) Find out the accelerations by using the graph!

5.7 a) geg: r = 1,0 m ges : v

F(gewicht) = F(zentral) m w2 r = m g /:m

w 2 = r g

w 2 = g : r

w 2 = 9,81 N/Kg : 1,0m

w = $$9,81$$

w = 3,13

v = w r

v = 3,13 * 1m

v = 3,13 m/s

b)

Rotor auf dem oktoberfest, mit Durchmesser d ,Boden wird abgesenkt ohne dass Körper (m= ...)abgleitet Welche Geschwindigkeit(wand)??