User:Garfrau

Aufgabe 4.6
a) $$E_k = \frac {1}{2}m*v^2 = \frac {1}{2}*2000kg*\frac {50}{3,6}\frac{m}{s} = 193kJ$$

b) $$E_p = m*g*h = 9,81 \frac {N}{kg}*200m*1000kg = 1962000J$$

c) $$E_k = \frac {1}{2}*4000000kg*1\frac{m}{s} = 2MJ$$