Mechanics11/Seite14/Loesung5.7

a)

v = $$g * r$$ = $$9,81 m/s2 * 1,0m$$ = 3,1m/s

b)

Epot = Ekin

m * g * h = 1/2 * m * v2 - 1/2 * m * v02

g * 2 * r = 1/2 * (v2 - v02)

4 * g * r = v2 - v02

v2 = v02 + 4 * g * r = (3,12 + 4 * 9,81 * 1,0) (m/s)2

=> v = 7,0 m/s

c)

h = v2/2*g = (3,1)2/(2*9,81) = 0,5m

Insgesamt fliegt die Dose 1.5m hoch.

--Chantal 08:20, 26 June 2008 (UTC)