Mechanics11/Seite9/Loesung3.5

m = 6,0t

m = 6000kg

F = 20 kN

a)

$$F = m*a $$

$$\frac{F}{m}= a$$

$$\frac{20000N}{6000kg}= a$$

$$=> 3,334\frac{m}{s^2}$$

b.)

$$\Delta t = \frac{\Delta v}{m}$$

$$\Delta t = \frac{360 \frac{km}{h}}{\frac{m}{3s^2}}$$

$$\Delta t = \frac{100 \frac{m}{s}}{\frac{m}{3s^2}}$$

$$\Delta t = 30 s \frac{}{}$$

--FatF 12:19, 7 December 2007 (CET)

c)

$$x(t)=\frac {1} {2}*a*t^2$$

$$x(t)=\frac {1}{2}*3,334\frac{m}{s^2}*(30s)=1500m=1,5km$$

Schülerlösung
geg: m = 6,0t F = 20kN

a) ges: a

a = $$\frac {F}{m}$$

a = $$\frac {20kN}{6,0t}$$

a = $$\frac {20000N}{6000kg}$$

a = 3,3m/s²

b) ges: t

v = 360km/h = 100m/s

t = $$\frac {V}{a}$$

t = $$\frac {100m/s}{3,3m/s^2}$$

t = 30,3s

c) ges: x

x = $$\frac {1}{a}$$ * t²

x = $$\frac {1}{2}$$ * 3,3m/s^2 * (30s)^2

x = 1485m = 1,5 km

von Natalia Dobrzycka 11B