User:Maedls123/Mathe

= Problem =

f(x)= (((cos(x)/tan(x))1/2)1/2)1/2 =(cos(x)/tan(x))1/8

=Solution=

f´(x)= 1/8 * (cos(x)/tan(x))1/8 - 1 * ((-sin(x) * tan(x)+ cos(x)* 1/(cos(x))2

= 1/8 * (cos(x)/tan(x))1/8 - 1 * ((-sin(x) * tan(x)+ 1/cos(x))