Mechanics11/Seite5/Loesung2.10

a)parabel:

y = k*x2

y = 0.5*x2

x(t) = 0.5*a*t2

a = 1$$\frac{m}{s^2}$$

Bsp: x(4s) = 0.5 * 1$$\frac{m}{s^2}$$ * (4s)2 = 8m

0 < t < 4s : x(t) = 0.5 * 1$$\frac{m}{s^2}$$ * t2

gerade:

y = m*x + t

v = $$\frac{\Delta x}{\Delta y}$$

$$\Delta x$$ = 0,8m

$$\Delta t$$ = 0,2s

=> v = $$\frac{0,8m}{0,2m}$$ = 4$$\frac{m}{s}$$

v = $$\frac{3,2m}{0,8s}$$ = 4$$\frac{m}{s}$$

x(t) = x0 + v*t

b)