Mechanics11/Seite11/Loesung4.4

$$ D = 6.0 \frac{N}{m}$$ ;  s = 2.0 cm = 0.02 m

$$W = \frac{1}{2} D s^2$$ $$ = \frac{1}{2} 600 0.02^2 = 0.12J$$

ESp = Ekin

$$ \frac{1}{2} D s^2 = $$ $$ \frac{1}{2} m v^2$$

$$v^2 = \frac{Ds^2}{m} = $$ $$ \frac{600N/m * 0.02m}{0.04kg}$$ $$ = \frac 60$$

v = $$60$$ = 7.7 m/s

-Marc Schuster, Sebastian Felsner, Maximilian Vrecko- :

$$D = 600 \frac {N}{m}$$

$$F = D*s$$

$$F = 600 \frac {N}{m} * 0,02m$$

$$F = 12 N$$

$$F = a*m$$

$$a = \frac {F}{m}$$

$$a = \frac {12 N}{0,00040 Kg}$$

$$a = 30000 \frac {m}{s^2}$$

$$v^2 = 2 * a * x$$

$$v = \sqrt[]{2*a*x}$$

$$v = \sqrt[]{2 * 30000 \frac {m}{s^2} * 0,02m}$$

$$v = 34, 6 \frac {m}{s}$$