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User:NikeAirM11

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a)
x(t)=x0+v* δt
Bussard:x(t)=14km+95 \frac {km}{h}* δt
Falke:x(t)=0km+153 \frac {km}{h}* δt
Gleichgesetzt:14km+95 \frac {km}{h}* δt=0km+153 \frac {km}{h}* δt


a) x(t)= x0+ Δt * v x(tFalke)= 14km+ 95km/h * Δt x(tBussard)= 0km+ 153km/h * Δt


x(tFalke)=x(tBussard) 14km + 95km/h * Δt= 153km/h * Δt 14km = 58km/h * Δt 0,24h=Δt 14min= Δt

b) x(0,24h) = 153km/h * 0,24h x(0,24h)= 36,7km x(14min)= 37km

c) Der Falke überholt den Bussard bei 37km und ist daher als erstes am Ziel.


Lösung zu: 1.11 Geblitzt !


a) xt = 0 + 340 \frac{m}{s} * \frac{0,3 * s}{2} 

  xt = 51m

  xt = 0 + 340 \frac{m}{s} * \frac{1 * s}{2}
  xt = 170


1.9 Rückwärtsgang

a)v=\frac {\Delta {x}} {\Delta {t}} 

 v=\frac {-168m} {12,5s}
 v=-13.4\frac {m} {s}

b)x(t) = x0 + v * Δt 

 x(t)=168m-13.4\frac {m} {s} * 173s
x(t)=2.16\frac {km} {h}

c)t=\frac {x(t)-x_0} {v} 

\frac {-6200m-168m} {-13.4\frac {m} {s}}

Lösung zu Aufgabe 2.7

geg.: v(t)=100km/h  ; t=3,87s

ges.: a  ; x(t)

Lsg.: a=\frac{v(t)}{t}=\frac{100\frac{km}{h}}{3,87s}=\frac{2,8\frac{m}{s}}{3.87s}=7.12\frac{m}{s^2}

x(t)=\frac{1}{2}*a*t^2=\frac{1}{2}*7.12\frac{m}{s^2}*(3,87s)^2=53,75m


Lösung zu 2.9

a)
t = \frac {v}{a}

t = 2,1*10-4


b)
x(t) = \frac{1}{2} * a * t 2
t= \frac {v}{a}



4.1: Brummi,Teil 2

c) W_a =\frac {m} {2}* v^2 

 17500kg * (13.89\frac {m} {s})^2 =3.4MJ

d1) P=\frac {W} {t} 

  \frac {3375750J} {40s}=84393.75W=84.4kW

d2) P=\frac {W_a +W_R} {t} 

  341.9kW

d3)WR = FR * x = 

  10.3MJ
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