Mechanics11/Seite9/Loesung3.7

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Gegeben:

m = 0,50 kg  ; v = 100 km/h


a)

Bremsweg: x = 10cm

v² = 2ax

a = v²/2x

a = (100km/h)² / 2*10cm

a = (27,78 m/s)² / 0,2m

a = 3858,642 m/s²

F = 0.5kg*3858 m/s² = 1918.2 N = 1.918 kN b)

2.Lösung

a) F = m*a

  a = [math]\frac {v}{t}[/math]
  v²= 2ax
  a = [math]\frac {v\ltsup\gt2\lt/sup\gt}{2x}[/math]
  a = [math]\frac {27.7m/s²}{0,2m}[/math]