Mechanics11/Seite5/Loesung2.10

a)parabel:

y = k*x²

y = 0.5*x²

x(t) = 0.5*a*t²

a = 1[math]\frac{m}{s^2}[/math]

Bsp: x(4s) = 0.5 * 1[math]\frac{m}{s^2}[/math] * (4s)² = 8m

0 < t < 4s : x(t) = 0.5 * 1[math]\frac{m}{s^2}[/math] * t²

gerade:

y = m*x + t

v = [math]\frac{\Delta x}{\Delta y}[/math]

[math]\Delta x[/math] = 0,8m

[math]\Delta t[/math] = 0,2s

=> v = [math]\frac{0,8m}{0,2m}[/math] = 4[math]\frac{m}{s}[/math]

v = [math]\frac{3,2m}{0,8s}[/math] = 4[math]\frac{m}{s}[/math]

x(t) = x₀ + v*t

b)