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Mechanics11/Seite15/Loesung5.12

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m_1 =47 kg m_2 =60kg G= 6,67*10^-11\frac{m^3}{kg*s^2}

F=\frac{m_1*m_2}{r^2}*G

F=6,67*10^-11*\frac{m^3}{kg*s^2}*\frac{60kg*47kg}{0,5m^2}

F = 7,5 * 10 − 11N

--Max 07:54, 26 June 2008 (UTC)

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