Mechanics11/Seite14/Loesung5.7

a)

v = [math]g * r[/math] = [math]9,81 m/s\ltsup\gt2\lt/sup\gt * 1,0m[/math] = 3,1m/s

b)

E_pot = E_kin

m * g * h = 1/2 * m * v² - 1/2 * m * v₀²

g * 2 * r = 1/2 * (v² - v₀²)

4 * g * r = v² - v₀²

v² = v₀² + 4 * g * r = (3,1² + 4 * 9,81 * 1,0) (m/s)²

=> v = 7,0 m/s

c)

h = v²/2*g = (3,1)²/(2*9,81) = 0,5m

Insgesamt fliegt die Dose 1.5m hoch.

--Chantal 08:20, 26 June 2008 (UTC)