Mechanics11/Seite14/Loesung5.4

1.Lösung:

[math]\;a = 9.81 \frac{m}{s^{2}} * 10 = 98 \frac{m}{s^{2}}[/math]

m kann vernachlässigt werden!

[math]\;=\gt F = m * a = 98N[/math]

[math]\;F_Z = m * \omega ^{2} * r[/math] [math]\;=\gt \omega ^{2} = \frac{F_Z}{(m * r)} = \frac{98N} {2000m} = 0,049[/math] [math]\;=\gt \omega = 0,0221s^{-1}[/math] [math]\;v = \omega * r = 0,221s^{-1} * 2000m = 442 \frac{m}{s}[/math]

[math]\;v ==\gt v = 1591 \frac {km} {h}[/math]

--P 08:14, 8 May 2008 (UTC)

--Kenny 08:14, 8 May 2008 (UTC)

--Chantal 08:14, 8 May 2008 (UTC)

Lösung 2:

[math]F_z = a_z = 10 * 9,81 N = 98,1 N[/math]

r = 2000m

m = 1

[math]F_z = m * w^2 * r[/math]

w = [math]\sqrt {\frac {98,1N} {2000m}}[/math]

w = 0,2215 ^-1

[math]v = w * r = 442,94 m/s = 1594,6 km/h = 1,6 * 10^3 km/h[/math]

--Gunacke 18:07, 8 May 2008 (UTC)