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Mechanics11/Seite14/Loesung.5.1

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a) T= \frac {5 *60}{13}s = 23s
f= \frac {1}{T} = \frac {1}{23}s= 0,043Hz
ω = \frac {2\pi}{T} = 2πf=0,272Hz
b) ω = \frac {\Delta \varphi}{t}
φ=ω * t= 0,272*10=2,72 entspricht 156°
t = \frac {\varphi}{\omega}

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