Mechanics11/Seite14/Loesung.5.1

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a) T= [math]\frac {5 *60}{13}s[/math] = 23s
f= [math]\frac {1}{T}[/math] = [math]\frac {1}{23}s[/math]= 0,043Hz
ω = [math]\frac {2\pi}{T}[/math] = 2πf=0,272Hz
b) ω = [math]\frac {\Delta \varphi}{t}[/math]
φ=ω * t= 0,272*10=2,72 entspricht 156°
t = [math]\frac {\varphi}{\omega}[/math]