Mechanics11/Seite11/Loesung4.7

Angabe

$\;a)$

$E_{kin} = \frac{1}{2}*m*v^2$

$E_{kin} = \frac{1}{2}*0,070*5,0^2 J$

$E_{kin} = \frac{}{} 0,875 J$

$E_{pot} = \frac{}{} m*g*h$

$E_{pot} = \frac{}{} m*g*2r$

$E_{pot} = \frac{}{} 0,070*9,81*2*0,50 J$

$E_{pot} = \frac{}{} 0,687 J$

$\;b)$

$\frac{}{}E_{kin'} = E_{kin0}$

$\frac{}{} => v' = v_0$

--FatF 09:12, 22 February 2008 (UTC)