Mechanics11/Seite11/Loesung4.7
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< Mechanics11 | Seite11
Angabe
- Masse m = 70g = 0,070 kg
- Geschwindigkeit v0 = 5,0 m/s
- Höhe h = 1,0 m
Rechnung
[math]\;a)[/math]
[math]E_{kin} = \frac{1}{2}*m*v^2[/math]
[math]E_{kin} = \frac{1}{2}*0,070*5,0^2 J[/math]
[math]E_{kin} = \frac{}{} 0,875 J[/math]
[math]E_{pot} = \frac{}{} m*g*h[/math]
[math]E_{pot} = \frac{}{} m*g*2r[/math]
[math]E_{pot} = \frac{}{} 0,070*9,81*2*0,50 J[/math]
[math]E_{pot} = \frac{}{} 0,687 J[/math]
[math]\;b)[/math]
[math]\frac{}{}E_{kin'} = E_{kin0}[/math]
[math]\frac{}{} =\gt v' = v_0[/math]
--FatF 09:12, 22 February 2008 (UTC)
