Mechanics11/Seite11/Loesung4.4

                   ;  s = 2.0 cm = 0.02 m

$W = \frac{1}{2} D s^2$ $= \frac{1}{2} 600 0.02^2 = 0.12J$

E_Sp = E_kin

$\frac{1}{2} D s^2 =$ $\frac{1}{2} m v^2$

$v^2 = \frac{Ds^2}{m} =$ $\frac{600N/m * 0.02m}{0.04kg}$ $= \frac 60$

v = $60$ = 7.7 m/s

-Marc Schuster, Sebastian Felsner, Maximilian Vrecko- :

$D = 600 \frac {N}{m}$

$F = D * s$

$F = 600 \frac {N}{m} * 0,02m$

$F = 12 N$

$F = a * m$

$a = \frac {F}{m}$

$a = \frac {12 N}{0,00040 Kg}$

$a = 30000 \frac {m}{s^2}$

$v 2 = 2 * a * x$

$v = \sqrt[]{2*a*x}$

$v = \sqrt[]{2 * 30000 \frac {m}{s^2} * 0,02m}$

$v = 34, 6 \frac {m}{s}$