Mechanics11/Seite11/Loesung4.4
[math] D = 6.0 \frac{N}{m}[/math] ; s = 2.0 cm = 0.02 m
[math]W = \frac{1}{2} D s^2[/math] [math] = \frac{1}{2} 600 0.02^2 = 0.12J[/math]
ESp = Ekin
[math] \frac{1}{2} D s^2 = [/math] [math] \frac{1}{2} m v^2[/math]
[math]v^2 = \frac{Ds^2}{m} = [/math] [math] \frac{600N/m * 0.02m}{0.04kg}[/math] [math] = \frac 60[/math]
v = [math]60[/math] = 7.7 m/s
-Marc Schuster, Sebastian Felsner, Maximilian Vrecko- :
[math]D = 600 \frac {N}{m}[/math]
[math]F = D*s[/math]
[math]F = 600 \frac {N}{m} * 0,02m[/math]
[math]F = 12 N[/math]
[math]F = a*m[/math]
[math]a = \frac {F}{m}[/math]
[math]a = \frac {12 N}{0,00040 Kg}[/math]
[math]a = 30000 \frac {m}{s^2}[/math]
[math]v^2 = 2 * a * x[/math]
[math]v = \sqrt[]{2*a*x}[/math]
[math]v = \sqrt[]{2 * 30000 \frac {m}{s^2} * 0,02m}[/math]
[math]v = 34, 6 \frac {m}{s}[/math]
