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Mechanics11/Seite11/Loesung4.3

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a)

D = \frac {F}{s}


D = \frac {50N}{0,80m}

D = 62,5 \frac {N}{m}


W_sp = \frac {1}{2} * D * s^2

W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 0,80m^2 = 20 J

b)

W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 1,30m^2 = 52,8 J

52,8J - 20J = 32,8J

c)

E = Wgesp.

=> E = 52,8J

-Marc Schuster, Sebastian Felsner, Maximilan Vrecko-


Zusätzliche Schülerlösung

geg.:

  • F = 50 N
  • s = 80 cm

ges.:

  • D
  • WSp

a)

D = \frac{F}{s}

D = \frac{50 N}{0,8 m}

D = 62,5 \frac{N}{m}


W_Sp = \frac{1}{2} D * s^2

W_Sp1 = \frac{1}{2} 62,5 \frac{N}{m} * (0,8 m)^2

W_Sp1 = 20 J \frac{}{}


b)

geg.: s_2 = 50 cm + 80 cm = 1,3 m

ges.: WSp2


W_Sp2 = \frac{1}{2} 62,5 \frac{N}{m} * (1,3 m)^2 - W_Sp1

W_Sp2 = 52,8 J - 20 J = 32,8 J \frac{}{}

c)

ges.: F

F = D * s \frac{}{}

F = 62,5 \frac{N}{m} * 1,3 m

F = 1,3 N \frac{}{}

--FatF 12:07, 25 January 2008 (CET)

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