Mechanics11/Seite10/Loesung3.18

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geg.: v1.Pfeil = 25 m/s , t = 2,0 s , v2.Pfeil = 30 m/s

a) ges.: Steighöhe h = x1

Lösung: v² = 2 g x

--> x1 = [math]\frac {v^2}{2g}[/math] = [math]\frac {(25 m/s)^2}{2*9,81 m/s^2}[/math] = 32 m

b) ges.: v

Lösung: --> -25 m/s = -v0

c) ges.: Steighöhe des 2. Pfeils x2

Lösung: x2 = [math]\frac {(30 m/s)^2}{2*9,81 m/s^2}[/math] = 46 m