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Mechanics11/Seite10/Loesung3.12

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1.Abschnitt: geschlossener Schirm


h = \frac{1}{2}at^2 = \frac{1}{2}*9,81\frac{m}{s^2}(5s)^2 = 122,6m


2.Abschnitt: geƶffneter Schirm


v = \frac{x}{t}

x = v*t = 7,5\frac{m}{s}*210s = 1537,5m



hges = 122,6m + 1537,5m = 1,7km