# Trigonometric Ratios of Complementary Angles

## Name

Trigonometric ratios of Complementary Angles
Figure Let
$\triangle AOH:\,$

$O=\text{ side adjacent to angle }\theta\,$

$A=\text{ side opposite to angle }\theta\,$

$H=\text{ hypotenuse}\,$

$\delta=90-\theta\,$

Trigonometrical

ratio of angle

$\theta\;$
Trigonometrical

ratio of complementary angle

$\delta=90-\theta\;$
Formulas
$\sin \theta=\frac{O}{H}$ $\cos \delta=\frac{O}{H}$ $\sin \theta=\cos \delta\,$ $\sin \theta=\cos (90-\theta)\,$
$\cos \theta=\frac{A}{H}$ $\sin \delta=\frac{A}{H}$ $\cos \theta=\sin \delta\,$ $\cos \theta=\sin (90-\theta)\,$
$\tan \theta=\frac{O}{A}$ $\cot \delta=\frac{O}{A}$ $\tan \theta=\cot \delta\,$ $\tan \theta=\cot (90-\theta)\,$
$\cot \theta=\frac{A}{O}$ $\tan \delta=\frac{A}{O}$ $\cot \theta=\tan \delta\,$ $\cot \theta=\tan (90-\theta)\,$
$\sec \theta=\frac{H}{A}$ $\csc \delta=\frac{H}{A}$ $\sec \theta=\csc \delta\,$ $\sec \theta=\csc (90-\theta)\,$
$\csc \theta=\frac{H}{O}$ $\sec \delta=\frac{H}{O}$ $\csc \theta=\sec \delta\,$ $\csc \theta=\sec (90-\theta)\,$

## Usage

• Write here usage for the table